## Predicted Yield

The Predicted yield is the predicted amount of product you will need in the equation

Example: If you have 5 bike frames and 10 tires, 5 bikes is the predicted yield

In order to figure out the predicted yield of the product

Your answer will be in grams

You ready for an example??

Here You go

Example

Example: If you have 5 bike frames and 10 tires, 5 bikes is the predicted yield

In order to figure out the predicted yield of the product

**First**: Locate the limiting reagent of the first two compounds**Second**: Find the Ratio between the Limiting Reagent and the Product you are looking for**Third**: Multiply the limiting Reagent by the ratio**Forth**: Multiply that number by the GFW of the Product you are looking forYour answer will be in grams

You ready for an example??

Here You go

Example

For the balanced equation shown below, if 29.2 grams of C4H8S were reacted with 61.5 grams of O2, how many grams of H2O would be produced?

2C_{4}H_{8}S_{}+15O_{2} Yields 8H_{2}O_{}+8CO_{2}+2SO_{3}

So

(If you forgot how to find the limiting reagent

The Limiting Reagent is Compound 2 or O2

15:8 or 1:.5333333

Which happens to be 1.921

(1.921)(.533333) ≈ 1.02453

The GFW of H2O = 18 (If you forgot how to locate the GFW Click Here)

(1.02453)(18) ≈ 18.4415

18.4415 g of H2O will be produced

Does That Make Sense??

Lets do one more

**First**We need to locate the limiting Reagent(If you forgot how to find the limiting reagent

__Click Here__)The Limiting Reagent is Compound 2 or O2

**Second**: Find the Ratio15:8 or 1:.5333333

**Third:**Multiply the molarity of limiting reagent by the ratioWhich happens to be 1.921

(1.921)(.533333) ≈ 1.02453

**Forth:**Multiply that number by the GFW of the product in questionThe GFW of H2O = 18 (If you forgot how to locate the GFW Click Here)

(1.02453)(18) ≈ 18.4415

18.4415 g of H2O will be produced

Does That Make Sense??

Lets do one more

Explanation 2

For the balanced equation shown below, if 11.00 grams of CO were reacted with 2.71 grams of H2, how many grams of C3H8 would be produced?

For the balanced equation shown below, if 11.00 grams of CO were reacted with 2.71 grams of H2, how many grams of C3H8 would be produced?

3CO_{}_{}_{}+7H_{2} Yields C_{3}H_{8}+3H_{2}O_{}

**First**: Find the Limiting Reagent

The Limiting Reagent is Compound 1 or 3CO

**Second:**Find the Ratio between the Limiting Reagent and the Product

3:1 or 1:1/3

Third: Multiply the molarity of the limiting reagent by the ratio

The molarity of the limiting reagent is .3928

(.3928)(1/3) ≈ .1309

Forth: multiply that number by the GFW of the product

C3H8 = 44

(.1309)(44) ≈ 5.761

5.761 grams of C3H8 will be produced

**Does that Make sense??**

You think you are ready for some practice problems

Click the Chicken below (8)

You think you are ready for some practice problems